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本篇內容主要講解“C++怎么實現連連看游戲”，感興趣的朋友不妨來看看。本文介紹的方法操作簡單快捷，實用性強。下面就讓小編來帶大家學習“C++怎么實現連連看游戲”吧!
struct GridInfor //記入擊中圖片信息
{
int idx,idy; //圖紙坐標
int leftx,lefty; //屏幕坐標
int GridID; //圖片類型
}pre,cur,dur;
struct //記錄連線點
{
int x;
int y;
}point[4];
static int pn; //記錄連線點個數
void InitFace (); //初始化界面
void Shuffle (); //隨即打亂圖片
void ShowGrid (); //顯示圖片
void RandGrid (); //繪制地圖
void Link (); //連接兩圖
void Des_direct (); //直接相消
void Des_one_corner(); //一折相消
void Des_two_corner(); //兩折相消
void Load_picture (); //加載圖片
void Init_Grid (GridInfor& pre); //初始化格子信息
void Leftbottondown (MOUSEMSG mouse); //實現鼠標左擊效果
void Draw_frame (int leftx,int lefty); //繪制邊框
void Mousemove (int leftx,int lefty); //實現鼠標移動效果
bool Judg_val (int leftx,int lefty); //判斷鼠標是否在游戲區
void SeleReact (int leftx,int lefty); //顯示選中效果
void TranstoPhycoor (int* idx,int* idy); //圖紙坐標轉變為屏幕坐標
void GridPhy_coor (int& leftx,int& lefty); //規范物理坐標
void iPaint (long x1,long y1,long x2,long y2); //將直線銷毀
void DrawLine (int x1,int y1,int x2,int y2) ; //用直線連接兩圖
bool DesGrid (GridInfor pre,GridInfor cur); //判斷兩者是否能相消
bool Match_direct (POINT ppre,POINT pcur); //判斷兩者是否能夠直接相消
bool Match_one_corner (POINT ppre,POINT pcur); //判斷兩者是否能一折相消
bool Match_two_corner (POINT ppre,POINT pcur); //判斷兩者是否能兩折相消
void ExchaVal (GridInfor& pre,GridInfor& cur); //交換圖片信息
bool Single_click_judge (int mousex,int mousey); //判斷單擊是否有效
void RecordInfor (int leftx,int lefty,GridInfor &grid); //記錄選中的信息
void TranstoDracoor (int mousex,int mousey,int *idx,int *idy); //鼠標坐標轉化為圖紙坐標
void Explot (POINT point,int *left,int *right,int *top,int *bottel);//探索point點附近的空位置接下來是我們隨機產生圖片的邏輯函數，這個要好好理解
void RandGrid() //產生圖片的標記
{
for(int iCount = 0, x = 1; x <= ROW; ++x )
{
for( int y = 1; y <= COL; ++y )
{
GridID[x][y] = iCount++ % GridNum + 1;
} } }
void Shuffle( ) //打亂棋盤
{
int ix, iy, jx, jy, grid;
for( int k = 0; k < 84; ++k )
{
ix = rand() % ROW + 1; // 產生 1 - COL 的隨機數
iy = rand() % COL + 1; // 產生 1 - ROW 的隨機數
jx = rand() % ROW + 1; // 產生 1 - COL 的隨機數
jy = rand() % COL + 1; // 產生 1 - ROW 的隨機數
if( GridID[ix][iy] != GridID[jx][jy] ) //如果不相等就交換數據
{
grid = GridID[ix][iy];
GridID[ix][iy] = GridID[jx][jy];
GridID[jx][jy] = grid;
} } }下面是我們的重點操作，鼠標控制函數，好好看好好學，寫的時候一定要有耐心，別被bug擊破了內心
void Mousemove (int leftx,int lefty) //鼠標移動時的變化
{
static int prex,prey,preidx,preidy, curidx,curidy;
if(Judg_val(leftx,lefty))
{
TranstoDracoor(leftx,lefty,&curidx,&curidy); //轉化為圖紙坐標
if(GridID[curidy][curidx] != 0)
{
GridPhy_coor(leftx,lefty);
if(pre.idx == preidx && pre.idy == preidy)
putimage(prex,prey,&image[GridID[preidy][preidx]][1]);
else
putimage(prex,prey,&image[GridID[preidy][preidx]][0]);
prex = leftx, prey = lefty;
preidx = curidx, preidy = curidy;
Draw_frame(leftx,lefty); //繪制邊框
} } }
void Leftbottondown (MOUSEMSG mouse) //左擊時的變化
{
static int click = 0, idx,idy;
click++;
SeleReact (mouse.x,mouse.y); //顯示選中效果
if(click == 1) RecordInfor(mouse.x,mouse.y,pre);
if(click == 2)
{
TranstoDracoor (mouse.x,mouse.y,&idx,&idy);
if(idx != pre.idx || idy != pre.idy)
{
RecordInfor (mouse.x,mouse.y,cur);
if(pre.GridID == cur.GridID && DesGrid(pre,cur))
{
GridID[pre.idy][pre.idx] = GridID[cur.idy][cur.idx] =0;
Link (); pn = 0;
putimage(pre.leftx,pre.lefty,&image2);
putimage(cur.leftx,cur.lefty,&image2);
Init_Grid(pre); Init_Grid(cur); click = 0;
}
else
{
ExchaVal(dur,pre); ExchaVal(pre,cur);
Init_Grid(cur); click = 1;
putimage(dur.leftx,dur.lefty,&image[GridID[dur.idy][dur.idx]][0]);
} }
else click = 1;
} }
void SeleReact (int leftx,int lefty) //選中時效果
{
if(Judg_val(leftx,lefty))
{
int idx,idy;
TranstoDracoor (leftx,lefty,&idx,&idy);
GridPhy_coor (leftx,lefty);
putimage(leftx,lefty,&image[GridID[idy][idx]][1]);
} }
bool Judg_val(int leftx,int lefty) //判斷鼠標是否在游戲區
{
return leftx > leftedge && leftx < leftedge + GridW * COL &&
lefty > topedge && lefty < topedge + GridH * ROW;
}
void TranstoDracoor (int mousex,int mousey ,int *idx,int *idy) //鼠標坐標轉化為圖紙坐標
{
if(Judg_val(mousex,mousey))
{
*idx = (mousex - leftedge) / 42 + 1;
*idy = (mousey - topedge) / 48 + 1 ;
} }
void RecordInfor(int leftx,int lefty,GridInfor &grid) //記錄選中的信息
{
TranstoDracoor(leftx,lefty,&grid.idx,&grid.idy);
grid.leftx = (grid.idx - 1) * 42 + leftedge;
grid.lefty = (grid.idy - 1) * 48 + topedge;
grid.GridID = GridID[grid.idy][grid.idx];
}
bool Single_click_judge (int mousex,int mousey) //判斷單擊是否有效
{
int idx,idy;
TranstoDracoor (mousex,mousey,&idx,&idy); //轉化為圖紙坐標
if(Judg_val(mouse.x,mouse.y) && GridID[idy][idx] != 0)
return true;
return false;
}
void Draw_frame(int leftx,int lefty) //繪制方框
{
setcolor(RGB(126,91,68));
setlinestyle(PS_SOLID,NULL,1);
rectangle(leftx,lefty,leftx+41,lefty+47);
rectangle(leftx + 2,lefty + 2,leftx+39,lefty+45);
setcolor(RGB(250,230,169));
rectangle(leftx + 1,lefty + 1,leftx+40,lefty+46);
}另外一個重點就是我們判斷函數了，第一次使用鼠標點擊棋盤中的棋子，該棋子此時為“被選中”，以特殊方式顯示；再次以鼠標點擊其他棋子，若該棋子與被選中的棋子圖案相同，且把第一個棋子到第二個棋子連起來，中間的直線不超過3根，則消掉這一對棋子，否則第一顆棋子恢復成未被選中狀態，而第二顆棋子變成被選中狀態。這個是重中之重，一定好好學，把其中的邏輯理解清楚，別只會Ctrl+c和Ctrl+v
bool DesGrid (GridInfor pre,GridInfor cur) //判斷兩者是否能相消
{
bool match = false; POINT ppre,pcur;
ppre.x = pre.idx; ppre.y = pre.idy;
pcur.x = cur.idx; pcur.y = cur.idy;
if(Match_direct(ppre,pcur)) match = true;
else if(Match_one_corner(ppre,pcur)) match = true;
else if(Match_two_corner(ppre,pcur)) match =true;
return match;
}
bool Match_direct(POINT ppre,POINT pcur) //判斷兩者是否能夠直接相消
{
int k,t;
if(ppre.x == pcur.x)
{
k = ppre.y > pcur.y ? ppre.y : pcur.y;
t = ppre.y < pcur.y ? ppre.y : pcur.y;
if(t + 1 == k) goto FIND;
for(int i = t + 1;i < k ;i++)
if(GridID[i][ppre.x] != 0) return false;
if(i == k) goto FIND;
}
else
if(ppre.y == pcur.y)
{
k = ppre.x > pcur.x ? ppre.x : pcur.x;
t = ppre.x < pcur.x ? ppre.x : pcur.x;
if(t + 1 == k) goto FIND;
for(int i = t + 1;i < k ;i++)
if(GridID[ppre.y][i] != 0) return false;
if(i == k) goto FIND;
}
return false;
FIND: point[pn].x = pcur.x, point[pn].y = pcur.y; pn++;
point[pn].x = ppre.x, point[pn].y = ppre.y; pn++;
return true;
}
bool Match_one_corner(POINT ppre,POINT pcur) //判斷兩者是否能一折相消
{
int left,right,top,bottel,x = ppre.x,y = ppre.y;
Explot(ppre,&left,&right,&top,&bottel);
ppre.y = top - 1;
RESEARCHX: if(ppre.y < bottel) ppre.y++;
else goto BACK;
if(Match_direct(ppre,pcur)) goto FIND;
else goto RESEARCHX;
BACK: ppre.y = y; ppre.x = left - 1;
RESEARCHY: if(ppre.x < right) ppre.x++;
else goto REBACK;
if(Match_direct(ppre,pcur)) goto FIND;
else goto RESEARCHY;
REBACK: pn = 0; return false;
FIND: point[pn].x = x,point[pn].y = y,pn++;
return true;
}
bool Match_two_corner(POINT ppre,POINT pcur) //判斷兩者是否能兩折相消
{
int left,right,top,bottel,x = ppre.x,y = ppre.y;
Explot(ppre,&left,&right,&top,&bottel);
ppre.y = top - 1;
RESEARCHX: if(ppre.y < bottel) ppre.y++;
else goto BACK;
if(Match_one_corner(ppre,pcur)) goto FIND;
else goto RESEARCHX;
BACK: ppre.y = y; ppre.x = left - 1;
RESEARCHY: if(ppre.x < right) ppre.x++;
else goto REBACK;
if(Match_one_corner(ppre,pcur)) goto FIND;
else goto RESEARCHY;
REBACK: pn = 0;return false;
FIND: point[pn].x = x,point[pn].y = y,pn++;
return true;
}
void Explot(POINT point,int *left,int *right,int *top,int *bottel)
{
int x = point.x,y = point.y; x++;
while(x <= COL + 1 && GridID[y][x] == 0) x++; *right = x - 1; x = point.x; x--;
while(x >= 0 && GridID[y][x] == 0) x--; *left = x + 1; x = point.x; y++;
while(y <= ROW + 1 && GridID[y][x] == 0) y++; *bottel= y - 1; y = point.y; y--;
while(y >= 0 && GridID[y][x] == 0) y--; *top = y + 1;
}最后用主函數調用，這樣就可以啦
void main()
{
initgraph(M,N);
mciSendString("play game_begin.mp3 repeat", NULL, 0, NULL);
InitFace();
while(1)
{
mouse = GetMouseMsg();
switch(mouse.uMsg)
{
case WM_MOUSEMOVE:
Mousemove(mouse.x,mouse.y); break;
case WM_LBUTTONDOWN:
if(Single_click_judge(mouse.x,mouse.y))
{
Leftbottondown(mouse);
} break;
default: break;
}
}
closegraph();
}到此，相信大家對“C++怎么實現連連看游戲”有了更深的了解，不妨來實際操作一番吧！這里是億速云網站，更多相關內容可以進入相關頻道進行查詢，關注我們，繼續學習！
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