溫馨提示×
您好，登錄后才能下訂單哦！
點擊 登錄注冊 即表示同意《億速云用戶服務條款》
您好，登錄后才能下訂單哦！
這篇文章主要介紹C++怎么實現趣味掃雷游戲，文中介紹的非常詳細，具有一定的參考價值，感興趣的小伙伴們一定要看完！
1.初始化陣列。
2.輸入坐標點。
3.選擇：挖掘，標記，取消標記，重啟，退出游戲。
如果選了挖掘，判斷坐標點是地雷則游戲結束，是數字則顯示數字并回到2，是空格則顯示周圍8個元素值并直到連帶的空格顯示完了回到2；
如果選了標記，將該點的元素值設為-2并回到2；
如果選了取消標記，初始化該點，回到2；
如果選了重啟，則初始化陣列，回到2；
如果選了退出游戲，則exit。
4.挖掘完所有非地雷點后，游戲勝利，選擇是否再來一局，是則回到1，否則exit
創建一個bombsweep類，存儲幾個方法:
calculate：統計以(x,y)為中心周圍8個點的地雷數目。
game：模擬游戲過程。
print:打印陣列。
check:檢查是否滿足勝利條件。
在main函數中，在需要的時候根據bombsweep類創建bs對象，調用bs里面的相關方法。
程序代碼
#include <ctime>
#include <cstdlib>
#include <iostream>
#include <cstring>
using namespace std;
int map[12][12]; // ??????????,????????????1
int derection[3] = { 0, 1, -1 }; //????????8?????
int type;
class bombsweep
{
public:
int calculate ( int x, int y )
{
int counter = 0;
for ( int i = 0; i < 3; i++ )
for ( int j = 0; j < 3; j++ )
if ( map[ x+derection[i]][ y+derection[j] ] == 9 )
counter++; // ???(x,y)?????8???????
return counter;
}
void game ( int x, int y )
{
if ( calculate ( x, y ) == 0 )
{
map[x][y] = 0;
for ( int i = 0; i < 3; i++ )
{
// ???????,?????????
for ( int j = 0; j < 3; j++ )
if ( x+derection[i] <= 9 && y+derection[j] <= 9 && x+derection[i] >= 1 && y+derection[j] >= 1
&& !( derection[i] == 0 && derection[j] == 0 ) && map[x+derection[i]][y+derection[j]] == -1 )
game( x+derection[i], y+derection[j] ); // ???????????????0,????????!
} //????????.???????????
}
else
map[x][y] = calculate(x,y);
}
void print (int x,int y)
{
cout << " |";
for (int i=1; i<10; i++)
cout << " " << i;
cout << endl;
cout << "__|__________________Y" ;
cout << endl;
for ( int i = 1; i < 10; i++ )
{
cout << i << " |";
for ( int j = 1; j < 10; j++ )
{
if(map[i][j]==-2)
cout <<" B";
else if ( map[i][j] == -1 || map[i][j] == 9 )
cout << " #";
else
cout << " "<< map[i][j];
}
cout << "\n";
}
cout << " X\n";
}
bool check ()
{
int counter = 0;
for ( int i = 1; i < 10; i++ )
for ( int j = 1; j < 10; j++ )
if ( map[i][j] != -1 )
counter++;
if ( counter == 10 )
return true;
else
return false;
}
};
int main ()
{
int i, j, x, y;
char ch;
srand ( time ( 0 ) );
do
{
//?????
memset ( map, -1, sizeof(map) );
for ( i = 0; i < 10; )
{
x = rand()%9 + 1;
y = rand()%9 + 1;
if ( map[x][y] != 9 )
{
map[x][y] = 9;
i++;
}
}
cout << " |";
for (i=1; i<10; i++)
cout << " " << i;
cout << endl;
cout << "__|__________________Y" ;
cout << endl;
for ( i = 1; i < 10; i++ )
{
cout << i << " |";
for ( j = 1; j < 10; j++ )
cout << " "<< "#";
cout << "\n";
}
cout << " X\n";
cout << "Please input location x,press enter then input location y: \n";
while ( cin >> x >> y )
{
cout << "Please select:1.dig, 2.sign, 3.cancel sign, 4.restart, 5.exit: \n";
cin >>type;
switch(type)
{
case 1:
{
if ( map[x][y] == 9 || map[x][y]==-2)
{
cout << "YOU LOSE!" << endl;
cout << " |";
for (i=1; i<10; i++)
cout << " " << i;
cout << endl;
cout << "__|__________________Y"<<endl ;
for ( i = 1; i < 10; i++ )
{
cout << i << " |";
for ( j = 1; j < 10; j++ )
{
if ( map[i][j] == 9 || map[i][j]==-2)
cout << " @";
else
cout << " #";
}
cout << "\n";
}
cout << " X\n";
exit(0);
}
bombsweep bs;
bs.game(x,y);
bs.print(x,y);
cout << "Please input location x,press enter then input location y: \n";
if ( bs.check())
{
cout << "YOU WIN" << endl;
break;
}
continue;
}
case 2:
{
bombsweep bs;
map[x][y]=-2;
bs.print(x,y);
cout << "Please input location x,press enter then input location y: \n";
continue;
}
case 3:
{
bombsweep bs;
map[x][y]=-1;
bs.print(x,y);
cout << "Please input location x,press enter then input location y: \n";
continue;
}
case 4:
{
memset ( map, -1, sizeof(map) );
for ( i = 0; i < 10; )
{
x = rand()%9 + 1;
y = rand()%9 + 1;
if ( map[x][y] != 9 )
{
map[x][y] = 9;
i++;
}
}
cout << " |";
for (i=1; i<10; i++)
cout << " " << i;
cout << endl;
cout << "__|__________________Y" ;
cout << endl;
for ( i = 1; i < 10; i++ )
{
cout << i << " |";
for ( j = 1; j < 10; j++ )
cout << " "<< "#";
cout << "\n";
}
cout << " X\n";
cout << "Please input location x,press enter then input location y: \n";
continue;
}
case 5:
cout << "Game Ended\n";
exit(0);
break;
default:
cout<< "Invalid input, try again: \n";
continue;
}//end switch
}//end while(cin >> x >>y)
cout << "Do you want to play again?(y/n):" << endl;
cin >> ch;
}//end do
while ( ch == 'y' );
return 0;
}//end main()以上是“C++怎么實現趣味掃雷游戲”這篇文章的所有內容，感謝各位的閱讀！希望分享的內容對大家有幫助，更多相關知識，歡迎關注億速云行業資訊頻道！
免責聲明：本站發布的內容（圖片、視頻和文字）以原創、轉載和分享為主，文章觀點不代表本網站立場，如果涉及侵權請聯系站長郵箱：is@yisu.com進行舉報，并提供相關證據，一經查實，將立刻刪除涉嫌侵權內容。
