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本篇內容主要講解“java怎么實現銀行家算法”,感興趣的朋友不妨來看看。本文介紹的方法操作簡單快捷,實用性強。下面就讓小編來帶大家學習“java怎么實現銀行家算法”吧!
本文實例為大家分享了java實現銀行家算法的具體代碼,供大家參考,具體內容如下
import java.util.Arrays;import javax.swing.JOptionPane;public class Banker_Dijkstra { static int available[]={3,3,2}; //可利用資源數 static int max[][]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};; //每線程最大需求 static int allocation[][]={{0,1,0},{2,0,0},{3,0,2},{2,1,1},{0,0,2}}; //已分配資源 static int need[][]={{7,4,3},{1,2,2},{6,0,0},{0,1,1},{4,3,1}}; //需求 static int request[]=new int[3]; //存放請求資源 static int thread; //線程號 static JOptionPane jpane = new JOptionPane(); // static boolean m; public static void main(String[] argv){ int n = 0 ; Banker_Dijkstra bd = new Banker_Dijkstra(); for(int i=0;i<5;i++){ if(bd.safeState(i)){ JOptionPane.showMessageDialog(jpane, "系統狀態安全"); n=1; break; }else{ n=2; continue; } } if(n==1){ bd.getThread(); } else if(n==2){ JOptionPane.showMessageDialog(jpane, "系統狀態不安全"); } } protected void getThread(){//輸入測試線程號且輸出結果 try{ String xiancheng = JOptionPane.showInputDialog(jpane,"請輸入申請資源的線程:"); thread = (int) Integer.parseInt(xiancheng); }catch(Exception e){ int response = JOptionPane.showConfirmDialog(jpane, "請輸入0~4:",null, JOptionPane.YES_NO_OPTION); // 處理異常 if(response==0){ getThread(); }else if(response ==1){ System.exit(0); } } if(thread<0||thread>4){ JOptionPane.showMessageDialog(jpane, "請輸入0~4:"); getThread(); }else{ for(int i=0;i<3;i++){ String requestR = JOptionPane.showInputDialog(jpane,"請輸入申請的第"+(i+1)+"種資源(若不申請則填0)"); try{ request[i]=Integer.parseInt(requestR);} catch(Exception e){ JOptionPane.showConfirmDialog(jpane, "請輸入申請的第"+(i+1)+"種資源(若不申請則填0)",null,JOptionPane.YES_NO_OPTION); } } if(request[0]>need[thread][0]||request[1]>need[thread][1]||request[2]>need[thread][2]){ JOptionPane.showMessageDialog(jpane,thread+"線程申請的資源超出其需要的資源,請重新輸入"); getThread(); }else{ if(request[0]> available[0]||request[1]> available[1]||request[2]> available[2]){ JOptionPane.showMessageDialog(jpane,thread+"線程申請的資源大于系統資源,請重新輸入"); getThread(); } } // 分配資源 allocateData(thread); // 判斷 繼續模擬選擇與處理 int tag=0; if(check(thread)){ try{ String str = JOptionPane.showInputDialog(jpane,"是/否 繼續模擬?( 1/0 ):"); tag = Integer.parseInt(str); }catch(Exception e){ JOptionPane.showMessageDialog(jpane, "繼續 輸入(數值) 1,不繼續 輸入(數值) 0 !"); } if(tag==1){ recoverData(thread); getThread(); } else{ if( (JOptionPane.YES_NO_OPTION)==JOptionPane.CANCEL_OPTION)System.exit(0); if((JOptionPane.YES_NO_OPTION)==JOptionPane.YES_OPTION) recoverData(thread); } }else{ recoverData(thread); getThread(); } } } // 安全算法 private boolean check(int thread2) { boolean[] finish = new boolean[5]; Arrays.fill(finish, false); int[] work = new int[3]; int[] queue = new int[5]; int q=0;//安全序列下標 for(int i = 0;i<3;i++){ work[i] = available[i]; } int tT = thread2; while(tT<5){ for(int R=0;R<3;R++){ if((!(finish[tT]==false))||(!(work[R]>=need[tT][R]))){ tT++; break; }else{ if(R==2){ for(int m =0;m<3;m++){ work[m] += allocation[tT][m]; } for(int s:work){ System.out.print(s+" "); } System.out.println(""); finish[tT] = true; queue[q] = tT; q++; tT =0; } } } } for(int p =0;p<5;p++){ if(finish[p]==false){ JOptionPane.showMessageDialog(jpane, "安全序列生成失敗"); return false; } } JOptionPane.showMessageDialog(jpane, "安全序列:"+queue[0]+","+queue[1]+"," +queue[2]+","+queue[3]+","+queue[4]); return true; } private boolean safeState(int thread3){ boolean[] finish = new boolean[5]; Arrays.fill(finish, false); int[] work = new int[3]; int[] queue = new int[5]; int q=0;//安全序列下標 for(int i = 0;i<3;i++){ work[i] = available[i]; } int tT = thread3; while(tT<5){ for(int R=0;R<3;R++){ if((!(finish[tT]==false))||(!(work[R]>=need[tT][R]))){ tT++; break; } else{ if(R==2){ for(int m =0;m<3;m++){ work[m] += allocation[tT][m]; } finish[tT] = true; queue[q] = tT; q++; tT =0; } }// if((finish[tT]==false)&&(work[R]>=need[tT][R])){// for(int m =0;m<3;m++){// work[m] += allocation[tT][m];}// finish[tT] = true;// queue[q] = tT;// q++;// tT=0;// }else{ // tT++;// break;// } } } for(int p =0;p<5;p++){ if(finish[p]==false){ return false; } } return true; } private void recoverData(int thread2) { // 生成失敗則重置已分配資源 for(int i=0;i<3;i++){ //重新調整系統資源數 available[i]+=request[i]; //計算各個線程擁有資源 allocation[thread2][i]-=request[i]; //重新計算需求 need[thread2][i]+=request[i]; } } private void allocateData(int thread2) { //分配 for(int i=0;i<3;i++){ //重新調整可用系統資源數 available[i]-=request[i]; //計算各個線程分配后擁有資源 allocation[thread2][i]+=request[i]; //重新計算需求 need[thread2][i]-=request[i]; } }}
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