中文字幕av专区_日韩电影在线播放_精品国产精品久久一区免费式_av在线免费观看网站

溫馨提示×

溫馨提示×

您好，登錄后才能下訂單哦！

密碼登錄×
登錄注冊×
其他方式登錄
點擊 登錄注冊 即表示同意《億速云用戶服務條款》

單鏈表快速排序

發布時間：2020-08-15 12:39:02 來源：ITPUB博客 閱讀：168 作者：21ca 欄目：編程語言

點擊(此處)折疊或打開

  1. public class LinkedListSortTest {
  2.     //bubble up
  3.     public static ListNode sortList(ListNode head) {
  4.         ListNode m = head;
  5.         ListNode tail = null;
  6.         while (m != tail && m.next != null) {
  7.             ListNode n = head;
  8.             while (n.next != null) {
  9.                 if (n.next.val < n.val) {
  10.                     swap(n, n.next);
  11.                 }
  12.                 n = n.next;
  13.             }
  14.             tail = n;
  15.             m = m.next;
  16.         }
  17.         return head;
  18.     }
  19.     
  20.     //quick sort
  21.     public static ListNode sortList2(ListNode head) {
  22.         ListNode next = head.next;
  23.         if (next == null) { // 1 element
  24.             return head;
  25.         } else if (next.next == null) { // 2 elements
  26.             if (head.val > next.val) {
  27.                 swap(head, next);
  28.             }
  29.             return head;
  30.         } else {
  31.             ListNode mid = getMidNode(head);
  32.             return merge(sortList(head), sortList(mid));
  33.         }
  34.     }


  37.     private static ListNode merge(ListNode m, ListNode n) {
  38. //        System.out.println("Merge " + m + " with " + n);
  39.         
  40.         ListNode head = new ListNode(0);
  41.         ListNode tail = head;
  42.         while (m != null && n != null) {
  43.             if (m.val < n.val) {
  44.                 tail.next = m;
  45.                 m = m.next;
  46.             } else {
  47.                 tail.next = n;
  48.                 n = n.next;
  49.             }
  50.             tail = tail.next;
  51.         }
  52.         if (m != null) {
  53.             tail.next = m;
  54.         }
  55.         if (n != null) {
  56.             tail.next = n;
  57.         }
  58. //        System.out.println("Merge result : " + head.next);
  59.         return head.next;
  60.     }

  62.     private static ListNode getMidNode(ListNode n) {
  63.         ListNode fast = n;
  64.         ListNode slow = n;
  65.         while (true){
  66.             if (fast.next != null) {
  67.                 fast = fast.next;
  68.                 if (fast.next != null) {
  69.                     fast = fast.next;
  70.                     slow = slow.next;
  71.                     continue;
  72.                 }
  73.             }
  74.             break;
  75.         }
  76.         ListNode mid = slow.next;
  77.         slow.next = null;
  78.         return mid;
  79.     }

  81.     private static void swap(ListNode n, ListNode m) {
  82.         int v = n.val;
  83.         n.val = m.val;
  84.         m.val = v;
  85.     }

  87.     public static void main(String[] args) {
  88.         ListNode head = new ListNode(0);
  89.         int i = 0;
  90.         ListNode n = head;
  91.         while (i++ < 20) {
  92.             n.next = new ListNode(i * 37 % 50);
  93. //            n.next = new ListNode(i);
  94.             n = n.next;
  95.         }

  97.         print(head);
  98.         print(sortList(head));
  99.         print(sortList2(head));

  101.     }

  103.     public static void print(ListNode n) {
  104.         while (n != null) {
  105.             System.out.print(n.val + " ");
  106.             n = n.next;
  107.         }
  108.         System.out.println();
  109.     }

  111. }

  113. class ListNode {
  114.     int val;
  115.     ListNode next;

  117.     ListNode(int x) {
  118.         val = x;
  119.     }
  120.     
  121.     public String toString() {
  122.         ListNode n = this;
  123.         StringBuilder sb = new StringBuilder("[");
  124.         while (n != null) {
  125.             sb.append(n.val + " ");
  126.             n = n.next;
  127.         }
  128.         sb.deleteCharAt(sb.length() - 1);
  129.         sb.append("]");
  130.         return sb.toString();
  131.     }
  132. }
來源于  https://leetcode.com/problems/sort-list/
148. Sort List 

Sort a linked list in O(n log n) time using constant space complexity.
向AI問一下細節

免責聲明：本站發布的內容（圖片、視頻和文字）以原創、轉載和分享為主，文章觀點不代表本網站立場，如果涉及侵權請聯系站長郵箱：is@yisu.com進行舉報，并提供相關證據，一經查實，將立刻刪除涉嫌侵權內容。

AI
助
手
临高县| 山阴县| 达拉特旗| 平昌县| 甘肃省| 阳谷县| 介休市| 竹北市| 德钦县| 塔河县| 南投市| 孟村| 临泉县| 无极县| 崇义县| 呼图壁县| 建宁县| 永川市| 宜宾市| 封开县| 贞丰县| 昭通市| 韩城市| 潞西市| 镇平县| 舞钢市| 尼木县| 双峰县| 巴彦县| 天镇县| 石屏县| 天祝| 阿尔山市| 延边| 福州市| 宁海县| 北票市| 濮阳市| 台中县| 泸州市| 于都县|